A bag contains eleven balls labeled 1 through 11. One ball will be randomly picked. What is the probability of picking an odd number?
Write your answer as a fraction in simplest form
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there is a one and a elevan chance at picking the ball

Step-by-step explanation:

i think it would be 6 in eleven  6/11

Step-by-step explanation:

there is six odd numbered balls in the bag 1, 3, 5, 7, 9, 11

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

i cant answer this, theres no table. sorry man

step-by-step explanation: