A $1200 investment is made. How much should be invested at 15% and how much at 8% so that the total return on the entire investment is 9.5%?

The amount invested at 15% = $257.14

The amount invested at 8% = $942.86

Step-by-step explanation:

Let the amount invested at:

15% = a

8% = b

Total invesment = $1200

Hence:

a + b= $1200 Equation 1

a = 1200 - b

15% × a + 8% × b = 9.5% × 1200

0.15a + 0.08b = 0.095 × 1200

0.15a + 0.08b = 114 Equation 2

We substitute 1200 - b for a in Equation 2

0.15(1200 - b) + 0.08b = 114

180 - 0.15b + 0.08b = 114

- 0.15b + 0.08b = 114 - 180

- 0.07b = - 66

b = -66/-0.07

b = $942.85714286

Approximately = $942.86

Note that:a = 1200 - b

a = $1200 - $942.86

a = $257.14

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0