PLEASE I NEED MAJOR HELP WITH THIS! In ΔABC shown below, segment DE is parallel to segment AC: Triangles ABC and DBE where DE is parallel to AC The following two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally: Statement Reason 1. Line segment DE is parallel to line segment AC 1. Given 2. Line segment AB is a transversal that intersects two parallel lines. 2. Conclusion from Statement 1. 3. 3. 4. 4. 5. ΔABC ∼ ΔDBE 5. Angle-Angle (AA) Similarity Postulate 6. BD over BA equals BE over BC 6. Converse of the Side-Side-Side Similarity Theorem Which statement and reason accurately completes the proof? (5 points) Question 4 options: 1) 3. ∠BDE ≅ ∠BAC; Corresponding Angles Postulate 4. ∠A ≅ ∠C; Isosceles Triangle Theorem 2) 3. ∠BDE ≅ ∠BAC; Alternate Interior Angles Theorem 4. ∠A ≅ ∠C; Isosceles Triangle Theorem 3) 3. ∠BDE ≅ ∠BAC; Corresponding Angles Postulate 4. ∠B ≅ ∠B; Reflexive Property of Equality 4) 3. ∠BDE ≅ ∠BAC; Alternate Interior Angles Theorem 4. ∠B ≅ ∠B; Reflexive Property of Equality