Given ∆ABC≅∆DEF, m∠A=5x+12 and m∠D=8x, find m∠A and m∠D.

Given :

Two triangle ∆ABC and ∆DEF are congruent.

m∠A=5x+12 and m∠D=8x.

To Find :

m∠A and m∠D.

Solution :

Since, both the triangle are congruent.

m∠A = m∠D

5x + 12 = 8x

3x = 12

x = 4

m∠A = 5(4) + 12 = 32°

m∠D = 8(4) = 32°

Therefore, value of m∠A and m∠D is 32°.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this