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Mathematics, 01.12.2020 14:00 mr1martin

In a poll of 500 American High School students, .75% (p¯=0.75p0.75) said that they used the Internet for social purposes at least once a day. The goal is to construct a 99% confidence interval for the percentage (pp) of American High School students who use the Internet for social purposes at least once per day around the period the poll was conducted.

The 99% confidence interval estimate of pp is

Select one:

a. 0.44 ± 0.002

b. 0.44 ± 0.03

c. 0.75 ± 0.15

d. 0.75 ± 0.05

Suppose around the period the above poll was conducted, a Internet Company CEO made a personal statement saying that .85% of American High School students use the Internet daily for social reasons.

In light of the sample evidence and at the 1% level of significance,

Select one:

a. We can reject the commentator's claim

b. We cannot reject the commentator's claim

A principal of a high school wishes to collect new random sample with the aim of building a new confidence interval at the 99% confidence level for pp.

Using the current sample proportion (from the 500 high school students poll ) as a basis, what sample size (n) would the journalist require to achieve a 10% margin of error?

Select one:

a. 125

b. 250

c. 73

d. 500

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Answers: 2

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