What is the volume of a sphere with a diameter of 2.2 ft, rounded to the nearest tenth of a cubic foot?

V≈5.58ft³     d=2.2 ft

Step-by-step explanation:

V=4  3πr3

d=2r

Solving for V

V=1  6π d3 =1  6·π·2.23≈5.57528ft³

Hope this helps! :D

5.6 ft  

Step-by-step explanation:

\text{Volume of a Sphere:}

Volume of a Sphere:

V=\frac{4}{3}\pi r^3

V=  

3

4

πr  

3

\text{radius} = \frac{\text{diameter}}{2} = \frac{2.2}{2}=1.1

radius=  

2

diameter

=  

2

2.2

=1.1

feet

\text{Plug in:}

Plug in:

\frac{4}{3}\pi (1.1)^3

3

4

π(1.1)  

3

5.57527976257

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi