subject
Mathematics, 01.12.2020 19:00 savvaggeb

Solve the following equation algebraically: -16 = 16x^2 How many solutions does this equation have? Explain.
a. -1=x^2: One solution because only -1 will satisfy the equation.
b. -1=x^2: No real solution because there is no real number that, when squared, produces -1.
C. 1=x^2: Two solutions because the square root of 1 is positive 1 and negative 1.
d. 1=-x^2: One solution because only -1 will satisfy the equation.


Solve the following equation algebraically:

-16 = 16x^2 How many solutions does this equation hav

ansver
Answers: 2

Another question on Mathematics

question
Mathematics, 21.06.2019 18:30
Use δjkl and δmpn to determine whether don's claim is true or false. which of the following should don use to prove the triangles are similar? sss sas aas aa
Answers: 1
question
Mathematics, 21.06.2019 20:00
Which of the following is not a subset of {1,2,3}?
Answers: 2
question
Mathematics, 21.06.2019 21:00
How to write four times a number,minus 6,is equal to theee times the number+8 as an equqtion
Answers: 2
question
Mathematics, 21.06.2019 21:30
Which of the following is a solution of z^6 = 64i? 2(cos105° + isin105°) 2(cos120° + isin120°) 2(cos135° + isin135°) 8(cos15° + isin15°)
Answers: 1
You know the right answer?
Solve the following equation algebraically: -16 = 16x^2 How many solutions does this equation have?...
Questions
question
Mathematics, 27.11.2021 03:20
question
Mathematics, 27.11.2021 03:20
question
Mathematics, 27.11.2021 03:20
question
Mathematics, 27.11.2021 03:30
question
Biology, 27.11.2021 03:30
question
Mathematics, 27.11.2021 03:30
Questions on the website: 13722361