An arrow is launched upward with a velocity of 96 96
feet per second from the top of a 50
50
-foot building. What is the maximum height attained by the arrow?

14

step-by-step explanation:

14 x 3 = 42

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

step-by-step explanation:

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94