Can someone help me with this

No, there is 3 times the amount of not yellow chalk than yellow chalk. This proves that the friend is wrong because this exceeds the given total amount of chalk, being 12. If the friend was correct there would be 24 pieces of not yellow chalk and 32 pieces of chalk in total.

The correct pieces of not yellow chalk is 9. The correct pieces of yellow chalk is 3. this can be solved by dividing the total, 12, by 4, because that is the total amount of units. This solves for one unit. Once you know the value of one unit, you can find the total of each type of chalk.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

multiply then divide

step-by-step explanation: