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Mathematics, 02.12.2020 01:00 yadirahurtado4444

4. If 100.0g of nitrogen gas (N2) is reacted with 100.0g of hydrogen gas (H2) to form NH3. What are the limiting and excess reactants? Hint: Convert grams to moles for each reactant and then convert to moles of NH3. You need your balanced equation from answer 1 to determine the mole relationship between each reactant and the product NH3. Use the periodic table to determine the molar mass of all chemical formulas. Fill in the โ€œ?โ€ blanks below to show your work.

Balanced equation: 1N2 (g) + 3H2(g) ๏ƒ  2NH3(g)

Molar mass of H2 = g/mol

100.0"g " "H" _2ร—(1"mol " "H" _2)/( ? "g " "H" _2 )ร—(" ? mol N" "H" _3)/(" ? mol " "H" _2 )= ? "mol N" "H" _3

Molar Mass of N2 = g/mol

100.0"g " "N" _2ร—(1"mol " "N" _2)/(" ? g " "N" _2 )ร—(" ? mole N" "H" _3)/(" ? mol " "N" _2 )= ? "mol N" "H" _3

A. What is the excess reactant? Hint: it is the reactant above that makes the most amount of product

B. What is the limiting reactant? Hint: it is the reactant above that makes the least amount of product

C. What is the theoretical yield of ammonia of the reaction?
Molar mass of NH3 = g/mol

100.0"g " "N" _2ร—(1"mol " "N" _2)/( ? "g " "N" _2 )ร—( ? "mol N" "H" _3)/( ? "mol " "N" _2 )ร—(" ? g N" "H" _3)/( 1 "mol N" "H" _3 )= ? "g N" "H" _3

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4. If 100.0g of nitrogen gas (N2) is reacted with 100.0g of hydrogen gas (H2) to form NH3. What are...
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