Determine whether g(x)=x2-5x+2 has a minimum of maximum

g(x) has a minimum

Step-by-step explanation:

Given a quadratic in standard form

g(x) = ax² + bx + c ( a ≠ 0 )

• If a > 0 then vertex is a minimum

• If a < 0 then vertex is a maximum

Given

g(x) = x² - 5x + 2 ← in standard form

with a > 0 , thus

g(x) has a minimum

50- 250 is correct i did that one too

step-by-step explanation:

a - base

b - exponent

so,