Let $p$ and $q$ be the two distinct solutions to the equation $$(x-3)(x+3) = 21x - 63.$$ If $p > q$, what is the value of $p - q$?

Given:

p and q are the two distinct solutions to the equation

To find:

The value of p-q if p>q.

Solution:

We have,

Using zero product property, we get

Here, 18>3, so p=18 and q=3.

Now,

Therefore, the value of p-q is 12.

30005

yes ok