Find 3 consecutive odd integers such that 10 times the first is 59 more than the third

9514 1404 393

  7, 9, 11

Step-by-step explanation:

Let x represent the middle integer. Then the first is x-2, and the third is x+2. The given relation is ...

  10(x -2) = 59 +(x +2)

  10x -20 = x +61 . . . . eliminate parentheses

  9x = 81 . . . . . . . . . . . add 20-x

  x = 9 . . . . . . . . . . . . . divide by 9

The integers are 7, 9, 11.

Check

  7·10 = 11 +59 . . . true

there will be 35 boys in each team. : )