A light tower is going to be installed on the left edge of the Skywalk as indicated in the diagram above. The light will shine down to the opposite edge of the Skywalk indicated with the star in the diagram above. How tall does the light tower need to be if the angle of depression is 51°?

The diagram indicating the light tower is below.

Tower has to be 86.45 ft high.

Step-by-step explanation: The second attachment shows the right triangle formed by the tower, the floor and the point the light will shine.

Using trigonometric relations among the angle and the sides of the triangle we will have:

h = 70*tan(51)

h = 86.45

The tower has to be 86.45 ft tall for the angle of depression to be 51°

the ratios are reciprocals im positive

step-by-step explanation:

they are all positive numbers so it wouldn't be the other ones

can someone me: the midsegment through the legs of an isosceles triangle is 4 in. find the sides of the triangle if its perimeter is 20 in. ,   and point g is the centroid of the right △abc with hypotenuse ab=18 in. find cg.