Write an equation of the line that passes through (7,10) and is perpendicular to the line y=12x−9.

An equation of the line that passes through (7,10) and is perpendicular to the line y=12x−9 is y - 10 = -1/12(x-7)

The equation of a line in point-slope form is expressed as;

y - y0 = m(x-x0)

Given the equation of a line y = 12x - 9

Substitute m = -1/12 and ()7, 10) into the equation above to have;

y - 10 = -1/12(x-7)

Hence an equation of the line that passes through (7,10) and is perpendicular to the line y=12x−9 is y - 10 = -1/12(x-7)

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y = - x +

Step-by-step explanation:

y = 12x - 9

Slope of line perpendicular to given is m = -

P(7, 10)

y - 10 = - (x - 7)

y = - x +

10

step-by-step explanation:

7+3=10

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step-by-step explanation:

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