HELP ME ASAP PLS tommy had 8 times more money than loren. when parents gived 35cents to loren and tommy spent 14cents both of kids had same money. how much tommy had in start? how much loren had in start?

Tommy had 56 cents in start and Loren had 7 cents in start.

Step-by-step explanation:

Let,

x be the money Tommy have.

y be the money Loren have.

According to given statement;

Tommy had 8 times more money than Loren.

x = 8y     Eqn 1

Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore

x-14=y+35    Eqn 2

Putting x=8y in Eqn 2

Dividing both sides by 7

Putting y=7 in Eqn 1

Hence,

Tommy had 56 cents in start and Loren had 7 cents in start.

i dont know and i dont care for math bc it is a stupied subject

step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine