_Se hizo un estudio donde arrojo que en el mall había 100 personas (entre hombres y mujeres) en el horario de las 12:00 pm., de los cuales 40 eran mujeres ,30 solicitaron horas por internet y 20 eran mujeres que solicitaron hora por internet. Si seleccionamos al azar un hombre la probabilidad que haya ido al mall sin solicitar hora en internet seria del 10%

2,600 divided by 80 = 32.5

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

something over 10 so ? /10

step-by-step explanation:

can you complete your sentence? i could !