A bee flies at 6 feet Per second directly to a flower bed from its hive. The bee stays at the flower bed for 19 minutes, and then flies directly back to the hive at 4 ft per second. Is away from the high for a total of 24 minutes. What equation can used to find the distance of the flower bed from the hive? How far is the flower bed from the hive?

720 feet

Step-by-step explanation:

We can Find the travelling time. We know that the bee spends 19 minutes hunting down the nectar in the flowerbed. But was away from the hive for a total of 24 minutes, then the travelling time becomes(24min - 19min) = 5 min

Then let us Convert to seconds vfir consistency

1 minute = 60 seconds

5 minutes = (5×60 )= 300 seconds.

Then the travelling time becomes 300 seconds

We can Find the time each way, since we know that the total time is 300 seconds, though not evenly divided

Let us denote the time there = t

the time back = (300 - t)

But the distances are the same.

r = 6 m/s and r1 = 4 m/s

t1 = t and t2 = (300 - t)

Let dthere = dback

Where, d =( rate × time)

(6× t )= 4 (300 - t)

6t= 1200 - 4t

10t=1200

t=120 seconds

To Find the distance?

d =( rate × time)

d = ? r = 6 m/s and t = 120 second

d = r*t

d = 6 × 120

= 720 feet

Hence, instance of the flower bed from the hive is 720 feet while the equation is ( d = r*t)

4th option is correct xy=-10

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step-by-step explanation: