Factor this polynomial completely x2 - 8x+ 12
O A. (x-2)(x-6)
B. (x + 2)(x-6)
c. (x - 2)(x+6)
D. (x-3)(x - 4)

(x-2)(x-6)

Step-by-step explanation:

We look for two integers which multiply to +12 but add to -8 and we find those numbers by looking at the factors of 12={1,2,3,4,6,12}

We find that by picking 6 and 2,6×2=12 but 6+2 is not -8 so we tweak that as -6 and-2

By so doing, now -6×-2=12,-6+(-2)=-8

so we factor to get (x-2)(x-6)

i think the answer is d im not sure