Hello I don't know what I'm doing can someone please help. I don't know how to solve a standard form slope equation can you please explain what I have to do.
The slope of the line 5x + y = 15 is___

x = -1/5y +3

Step-by-step explanation:

add -y to both sides

5x + y + -y = 15 + -y

5x = -y + 15

step 2 divide both sides by 5

5x/5 = -y +15/5

x= -1/5 y +3

Answer

x= -1/5 y + 3

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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