Suppose s and t are mutually exclusive events. find p(s or t). p(s) = 20%, p(t) = 22%

S and P are mutually exclusive events.
P ( S ) = 20% = 0.20
P ( T ) = 22 % = 0.22
The probability of mutually exclusive events:
P ( S or T ) = P ( S ) + P ( T )
P ( S or T ) = 0.20 +0.22 = 0.42
The probability of ( S or T ) is 0.42 or 42 %. 

There is no graph to go along with this

Sorry can u repeat that?