Which sequence of transformations performed on shape I confirms the congruence of shape II and shape I? A.
a reflection across the y-axis and then a translation down 16 units
B.
a 90° counterclockwise rotation about the origin and then a translation down 8 units
C.
a 90° clockwise rotation about the origin and then a translation left 16 units
D.
a 180° rotation about the origin and then a translation left 8 units

2.83941151 would be the answer you're looking for! : )

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

answer: i dont know i want points

step-by-step explanation: