The length of a rectangle is twice its width, while the perimeter of the rectangle is 36 units. . Which system of
equations can be used to find the length ( and the width w
of the rectangle?

Length = 12 units

Width = 6 units

Step-by-step explanation:

Let the width of the rectangle be represented by x.

Since the length of a rectangle is twice its width, thus means that the length will be: = 2x

Perimeter of a rectangle = 2(l + w)

where,

L = length

W = width

Therefore,

Perimeter = 2(l + b)

36 = 2(2x + x)

36 = 2(3x)

36 = 6x

x = 36/6

x = 6

Width = 6 units

Length = 2 × Width = 2 × 6 = 12 units

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

i'm not really sure how to answer that

step-by-step explanation: