Quadrilateral PQRS has points P = (–3,3), Q = (1,–4), R = (5,3), and S = (2,14). Quadrilateral P'Q'R'S' has points P' = (–3,–3), Q '= (1,4), R' = (5,–3), and S '= (2,–14). What is the transformation of PQRS to P'Q'R'S'?

(

1

,

3

)

,

(

−

6

,

−

4

)

,

(

−

2

,

3

)

Step-by-step explanation:

answer: i think one of the answer is $150 and $300?

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a