Calcium-41 is being used in studies testing the effectiveness of drugs for preventing osteoporosis. The half-life of calcium-41 is 100,000 years. If 20 grams of calcium-41 are present initially, how long would it take until only 2 grams remains?

332,193 years

Step-by-step explanation:

From the question above, we are to calculate the time in an half life question, hence, the formula is given as

t = In(Nt/No) ÷ -(In2/t½)

Where

t = time is takes for an substance to decay or reduce

Nt = Amount of sample after time = 2g

No = Initial amount of sample = 20g

t½ = Half life = 100,000 years

Hence,

t = In(2/20) ÷ (In 2/ 100,000)

t = 332192.80948874 years

Approximately = 332,193 years

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