When buying a candy bar, there is a 20% chance that it will also include a coupon for a second candy bar. A student wants to determine the probability that, if she buys 7 candy bars, more than 2 will include a coupon. To do this, she uses a random number table to pick 7 numbers from 1 to 5. She lets 1 represent a candy bar with a coupon and numbers 2 through 5 represent a candy bar without a coupon.. She repeats this for a total of 16 trials. The results are shown in the table. To estimate the probability that more than 2 out of 7 candy bars will include a coupon, the student must count the number of trials with and divide by the number of trials. This gives an estimated probability of about

Step-by-step explanation: To estimate the probability that more than 2 out of 7 candy bars will include a coupon, the student must count the number of trials with more than two 1's. and divide by the number of trials.

This gives an estimated probability of about 0.1875.

Step-by-step explanation:

1 represent a candy bar with a  coupon and numbers 2 through 5 represent a candy bar without a coupon.

Now we are asked to find the probability that, if she buys 7 candy bars, more than 2 will include a coupon.

Total number of outcomes=16

Number of favorable outcomes(i.e. the outcome which have more than 2 one) = 3

( Since the outcomes are:  2113415 4341112   1455141 )

Hence, the probability is the ratio of Number of favorable outcomes to the total number of outcomes.

i.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

take it another