How do you write an equation of a line that is parallel line to y=8x-8 through the point (5,2)

Parallel means that the two equations have the same slope,

so we have y = 8x + b so far.

Then we can just apply the slope to the given point by taking the y value and decreasing it by 40, due to the x value being 5

So in short, the equation that runs parallel to y = 8x-8 and intersect the point (5,2) is y = 8x -38