P =1/2kx^2 The seat on a tractor is mounted on springs in order to absorb impact. The driver sits on the seat,
and the springs compress a distance of a meters, m. As the springs compress, potential energy,
p, in joules (J), is stored in them according to the equation above. The spring constant, k,
describes the strength of the springs in newtons per meter 1. If the springs have a spring constant of 25,600N/m how much must the springs stretch, in meters, in order to store 8 J of
potential energy?

A
0.000625 meters
В
0.025 meters
1
3200 meters
D
102,400 meters