In the diagram above, mZABC = (3x-1), mZCBD = (2x)°, and mZDBE = (4x + 1)º. Find mZABC, mZCBD, and mZDBE. Assume that ZABE is a straight angle.
A. ZABC = 290, mZCBD = 20°, and mZDBE = 1319
B. ZABC = 59°, mZCBD = 20°, and mZDBE = 101°
C. m ABC = 59, mZCBD = 40°, and MZDBE = 81°
Dm ABC = 61º, mZCBD = 390, and mDBE = 80°

Step-by-step explanation:

3x -1 +2x + 4 x +1 = 180

9x = 180

X= 20

<ABC = 59

< CB D = 40

< DBE = 81

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0