Help, this is due at 12!! A soccer ball is kicked in the air with a vertical velocity of 20 m/s. Its height, h metres, t seconds after it is kicked can be represented by the equation h = –5 (t – 2)2 + 21.

What is the maximum height of the ball?

When did the ball reach its maximum height?

How high was the soccer ball above the ground when it left the kicker’s foot?

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

idk lol xd

step-by-step explanation:

ez do it yourself lazy

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two