You purchased concentrated cleaner that must be diluted (watered down) before use. Container A is the cleaner, which is a 20% solution. Container B is pure water. You are mixing together the contents of Container A and Container B to produce 40 gallons of 9% solution. How many gallons from each container are needed to create the 40 gallons of 9% cleaning solution? Write your answers as integers only. Container A: 20% Cleaning Solution =

gallons

Container B: Pure Water =

gallons

Amount of chemical solution = 18 gallon

Amount of pure water = 22 gallon

Step-by-step explanation:

Assume;

20% of solution = x

So,

Amount of pure water = 40 gallons - x

Amount of pure water = 40 - x

Computation:

20% of x = 9% of 40 gallon

0.2 x = 3.6

x = 3.6 / 0.2

x = 18 gallon

So,

Amount of chemical solution = 18 gallon

Amount of pure water = Total solution - Amount of chemical solution

Amount of pure water = 40 -18

Amount of pure water = 22 gallon

the correct answer is d

hope this

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b