No calculator If r + 9 is 4 more than s, then r-11 is how

much less than s?

A) 9

B) 11

C) 16

D) 20

16

Step-by-step explanation:

Given that :

r + 9 = 4 greater Than s

r - 1 1 is how much less than s

r + 9 = s + 4

Solve for r

Subtract 9 from both sides

r + 9 - 9 = s + 4 - 9

r = s - 5

Hence,

r - 11 = (s - 5) - 11

r - 11 = s - 5 - 11

r - 11 = s - 16

r - 11 = s - 16

Therefore, r - 11 is 16 less than s

just sum

10 + 10 = 20