What is the best substitution to make to evaluate the integral of the product of 4 minus x and 5 raised to the 4 minus x quantity squared, dx ? here I've stated it differently(it's the same integral): integral (4-x)5^(4-x)^2 dx
Answers:
u = 4 - x
u = (4 - x)2
u = 5(4 - x)
u = -x

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

no

step-by-step explanation:

answer