A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 124 feet per second from an initial height of 80 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation: h=−16t^2+124t+80
Find the two points in time when the object is 125 feet above the ground. Round your answers to the nearest hundredth of a second (two decimal places).