Sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24m, determine the sides of the two sqares.

Step-by-step explanation:

square = 468 m² x² + (6+x)² = 468 [Area of a square = side²] x² + (6)² + x² + 2×6×x= 468 [(a+b)²= a²+b²+2ab] 2x² + 36 + 12x= 468 2x² + 12x + 36 - 468= 0 2x² + 12x + 36 - 432 = 0 2(x² +6x - 216)= 0 x² +6x - 216 = 0 x² +18x -12x -216 =0

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.