Find all real zeros of the function f(x) = 5x (x-16)² (x-2)²

0, 16, and 2

Step-by-step explanation:

if tou find the zeros that are on the x-axis then y =f(x) =0

5x*(x-16)²(x-2)² =0

use de zero product rule and make each term = to 0 and find x

5x=0 so x=0/5 = 0

(x-16)² = 0 is x-16 = 0 so x=16

(x-2)²=0 is x-2=0 so x=2

answer: i can’t tell you that

step-by-step explanation: