PLEASE HELP I AM STRUGGLING! Maricela needs to write instructions for how to construct a regular hexagon inscribed in a circle. She begins by writing the following two steps:

Step 1: Start by drawing a cirlce using compass.
Step 2: Mark a point on the circle.

What is the best statement for Maricela to write for Step 3?

A. Using a straighedge, draw a segment that passes theough the marked point to the center of the circle.

B. Without changing the width of the compass, put the compass point ar the marked point, then draw and arc that intersects the circle in two places.

C. Using a straightedge, deaw a line segment from the center of the circle through the marked point, then extend the segment and label a point outside the circle.

D. Widen the radius of the compass to the width of the diameter, then place the compass point at the marked point and draw an arc that intersects the circle in one place.

The answer is B, without changing the width of the compass, put the compass point at the marked point, then draw an arc that intersects the circle in two places.

Step-by-step explanation:

This will mark spots all around the circle to form your hexagon

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

step-by-step explanation: