A line with a slope of 3 is written in the form y = mx + b. What is the value of b if the line passes through the point (3, 11) ?

Please show ALL work

b =2

Step-by-step explanation:

Since the slope is 'm', 3=m

y = (3)x + b

11 = 3(3) + b

11 = 9 + b

-9 from both sides

2 = b

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

it's d

step-by-step explanation: