Eliminate the parameter “t” for the parametric equations, where 0 < t < 5. x = √5t

y = 2t — 2

Answers:

A) y = 2/5x^2 — 2
B) y = 5/2X^2 — 5
C) y = 2√5x — 2
D) y = 2/5x^2 — 2

A) y = 2/5x^2 — 2

Step-by-step explanation:

We are given the parametric equation:

To express y in terms of x, we solve for t in the first equation and substitute in the second equation.

Squaring:

Solving for t:

Substituting in the second parametric equation:

Correct choice: A) y = 2/5x^2 — 2

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068