Anton is constructing an angle congruent to ∠PQR. With his straightedge, he draws and labels AB−→. He places the compass point on point Q and draws an arc that intersects QP−→− and QR−→−. He labels the point where the arc intersects QP−→− as point S and the point where the arc intersects QR−→− as point T. What should Anton do next?

With the same compass opening, place the compass point on point S and draw an arc through QR−→−.

Open the compass so that the compass point is on point Q and the pencil point on point P. Then place the compass point on point A and draw an arc through AB−→.

With the same compass opening, place the compass point on point A and draw a long arc through AB−→.

Open the compass so that the compass point is on point S and the pencil point on point T. Then place the compass point on point A and draw an arc through AB−→.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.