a plane is located on radar by an air traffic controller. what are the magnitude and the direction angle of the vector from the airport to the plane?

C The magnitude is 7.94, and the direction angle is N 49.91° E.

magnitude formula: sqrt x^2+y^2

                                 sqrt 6^2+5.2^2

                                 7.94

direction angle: tan^-1(x/y)

                          tan^-1(6/5.2)

                          49.91                      (convert radians to degrees)

The magnitude is 11.2, and the direction angle is E 40.91° N.

Step-by-step explanation:

edge

y > 1/3x

y < = -x + 4

hope this : )

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1