Michael jogs at 3 miles per hour and Jack runs at 4.5 miles per hour. If Michael starts at 2:00 pm and Jack starts on the same course at 2:20 pm, at what time and mileage will Jack catch up to Michael?

It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.

Step-by-step explanation:

Micheal  runs 3 miles in one hour or 60 minutes.

In one minute he runs 3/60= 1/20  or 0.05miles.

Jack runs 4.5 miles in one hour or 60 minutes.

In one minute he runs 4.5/60= 45/600= 9/120= 3/40  or 0.075 miles.

So Jack is 0.075/0.05 = 1.5 times faster than Micheal.

or Micheal is 1.5 times slower than Jack.

Jack starts from 2:20 pm and at 3 pm he will run 0.075(40 minutes)= 3miles

Micheal start at 2:00 pm and at 3 pm he will run 0.05(60 minutes)= 3 miles

So at 3 pm both will have covered equal distance= 3miles.

It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.

answerim :

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im not sure but my dad knows

70 years.

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