As part of the underwriting process for insurance, each prospective policyholder is tested for high blood pressure. Let X represent the number of tests completed when the first person with high blood pressure is found. The expected value of X is 12.5. Calculate the probability that the sixth person tested is the first one with high blood pressure.

0.053

Step-by-step explanation:

This is a geometric distribution problem.

I'm geometric distribution problem,

E(X) = 1/p

Where;

E(X) is expected value and p is probability of success

Thus;

1/p = 12.5

p = 1/12.5

p = 0.08

Now, to find the probability that the sixth person tested is the first one with high blood pressure, we will use the probability formula in geometric distribution which is;

P(X = k) = qⁿ•p

q = 1 - p

q = 1 - 0.08

q = 0.92

Thus;probability that the sixth person tested is the first one with high blood pressure will be expressed as;

P(X > 5) = (0.92^(5)) × 0.08

P(X > 5) = 0.053

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

except if the answer is in the value of money, then, it will matter. it will have to be $0.40, but i can tell this is not a money question, so .4 should be the right one.