Triangle ABC is an isosceles triangle with angle B as the vertex angle. Find the perimeter if AB = 6x + 3, BC = 8x - 1, and AC = 10x - 10. Perimeter = units

If triangle ABC is an isosceles triangle, angle B is the vertex angle, AB=6x+3 BC=8x-1 and AC=10x-10 find x and the measures of each side of the triangle

ABC is an isosceles triangle, angle B is the vertex angle..hence BA=BC..or..AB=BC...hence...

6x+3=8x-1

8x-6x=3+1=4

2x=4

x=4/2=2

so the 3 sides are

AB=6x+3=6*2+3=12+3=15

BC=8x-1=8*2-1=16-1=15

AC=10x-10=10*2-10=20-10=10

(sorry if i got ur answer wrong)

:(

168

step-by-step explanation:

i am pretty sure that the answer is 168

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b