A can of tuna fish has a diameter 11.4 cm and height 3.7 cm. Cans are packed snugly for shipping in boxes containing 4 layers of 5 rows by 7. How much empty space does each box contain?

14447 cm³

Step-by-step explanation:

Given that:

Diameter = 11.4cm

Height = 3.7cm

boxes has 4 layers ; 5 rows by 7

Hence, dimension of shipping boxes :

Height = height of can * layer = 3.7 * 4 = 14.8 cm

Length = 5 * diameter of can = 5 * 11.4 = 57cm

Width = 7 * diameter of can = 7 * 11.4 = 79.8 cm

Volume of shipping boxes :

Height * Length * Width

14.8 * 57 * 79.8 = 67319.28 cm³

For fish can:

Radius = diameter / 2 = 11. 4 / 2 = 5.7cm

Volume (V) of can = pi*radius^2*height

V = π * 5.7^2 * 3.7 = 377.66027 cm³

Total volume of cans = number of cans * V

Total volume of cans = (4 * 5 * 7 * 377.66027)

Total volume of cans = 52872.4378 cm³

Empty space = difference in volume

= 67319.28 - 52872.4378

= 14446.8422

= 14447 cm³ (approx)

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol