Write the equation of a line perpendicular to y =
3
x-3 and whose y-intercept is (0,12).

y=-1/3x+12

Step-by-step explanation:

The slope of a line that is perpendicular to another is the negative reciprocal of the first. The slope of the line is 3 so the negative reciprocal will be -1/3.

Using the point-slope formula we can solve for the  equation of a line with a slope of -1/3 and a point of (0,12).

The point slope formula is

y-y1=m(x-x1).

y-12=-1/3(x-0) >Distribute: y-12=-1/3x > Isolate the y by moving the 12 to the other side. y=-1/3x+12  

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

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step-by-step explanation:

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