Given \qquad m \angle LON = 77^\circm∠LON=77
∘
m, angle, L, O, N, equals, 77, degrees
\qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44
∘
m, angle, L, O, M, equals, 9, x, plus, 44, degrees
\qquad m \angle MON = 6x + 3^\circm∠MON=6x+3
∘
m, angle, M, O, N, equals, 6, x, plus, 3, degrees
Find m\angle MONm∠MONm, angle, M, O, N:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

the answer is 13/48

step-by-step explanation:

$649.60

step-by-step explanation: