Suppose p varies jointly as the cube root of q and the cube of r. If p = 1 when q = 4 and r = 2, what is p if q = 11 and r = 6?

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

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i hope this with your