Write an equation of the line in slope-intercept form.

f(3)=-2, f(0)=1

The equation of the line in slope-intercept form is y = -x + 1

Step-by-step explanation:

The slope-intercept form of the linear equation is y = m x + b, where

The rule of the slope is m = , where

∵ f(x) = y ⇒ is the function of the set of ordered pairs (x, y)

∴ f(3) = -2 is the point (3, -2)

∴ f(0) = 1 is the point (0, 1)

∴ x1 = 3 and y1 = -2

∴ x2 = 0 and y2 = 1

→ Substitute them in the rule of the slope to find it

∵ m = = =

∴ m = -1

→ Substitute it in the form of the equation above

∵ y = -1(x) + b

∴ y = -x + b

∵ b is the value of y at x = 0

∵ at x = 0, y = 1

∴ b = 1

∴ y = -x + 1

∴ The equation of the line in slope-intercept form is y = -x + 1

but which class are u may know that first

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.