A cylindrical tank has a radius of 5.5 ft and an altitude of 16 ft. If a gallon of paint will cover 130ft^2 of surface, how much paint is needed to put two coats of paint on the entire surface of the tank?

Step-by-step explanation:

First we need to calculate the Total surface area of the cylindrical tank as shown;

TSA of the tank = 2πr² + 2πrh  

TSA of the tank = 2πr(r+ h)  where;

r is the radius of the tank

h is the height

Given

radius = 5.5ft

height = 16ft

Get the surface area;

TSA = 2π(5.5)(5.5+ 16)

TSA = 2π(5.5)(21.5)

TSA = 2π(118.25)

TSA = 2(3.14)(118.25)

TSA = 742.61ft²

If a gallon of paint will cover 130ft^2 of surface, then the total number of paint needed will be;

Total number of paint needed = 742.61/130

Total number of paint needed = 5.7

For one coat we will need 5.7gallons of paint

For two coats we will need 2 * 5.7gallons = 11.4

Hence approximately 11 gallons of paints will be needed for the two coats

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180